The RC circuit shown in the figure has resistance of R = 7, 6 kΩ and the capacitance of C = 3, 2 μF. The capacitor is initially charged at a voltage V0 = 34, 3 V at t = 0, when the switch is closed. How long does it take for the current running in the circuit to go down to 49% of its initial value? Express your answer in units of ms (milliseconds) using two decimal places.