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  • Physics Archive: Questions from 2024-11-23

    If the coefficient of kinetic friction between an object with mass M = 3.00 kg and a flat surface is μk = 0.500, what force will cause the object to accelerate at 2.50 m/s2? The force is applied at an angle of θ = 30.0∘ (see the figure below). Calculate the force. (Express your answer to three significant figures.)

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    Convert the following quantities to the SI units indicated (report your answers to 3 significant digits using the appropriate prefixes). (a) 34.0 slugs/ft3 to kg/m3 kg m3 (b) 19.0 mph to m/s m s (c) 4.20 ft/hr to mm/s mm s

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    Three charges with a charge of +5 μC(+5×10−6 C) and one charge with a charge of −2 μC are situated as shown in the diagram with THE NEGATIVE CHARGE AT THE ORIGIN (each grid line is separated by 1 meter). The point (0, −2) is located half-way between the lower two charges on the y-axis. 8) What is the direction of the net electric field at the point (0, −2)? a) up b) down c) left d) right e) the electric field is zero 9) What is the magnitude of the net electric field at the point (0, −2)? a) 0 N/C b) 1688 N/C c) 2688 N/C d) 3688 N/C e) 4688 N/C 10) What is the net electric potential at the point (0, −2)? a) −47,250 V b) −27,250 V c) 0 V d) +27,250 V e) +47,250 V

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    What is the force on the charge located at x = 8.00 cm in Figure 18.52(a) given that q = 1.00 μC? Figure 18.52 (a) Point charges located at 3.00, 8.00, and 11.0 cm along the x-axis. (b) Point charges located at 1.00, 5.00, 8.00, and 14.0 cm along the x-axis. 42. (a) Find the total electric field at x = 1.00 cm in Figure 18.52(b) given that q = 5.00 nC. (b) Find the total electric field at x = 11.00 cm in Figure 18.52(b). (c) If the charges are allowed to move and eventually be brought to rest by friction, what will the final charge configuration be? (That is, will there be a single charge, double charge, etc., and what will its value(s) be?)

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    Calculate the moments Mx and My and the center of mass of a lamina with the given density and shape. ρ = 9 Mx = My = (x¯, y¯) = ()

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    Charge q1 = +q is located at position (0, d). Charge q2 = −2q1 is located at position (d, 0). Charge q3 = 7q1 is located at position (2d, 2d). Determine the net electric field E→net at the origin in terms of the given quantities and physical constants, including the permittivity of free space ε0. Express the electric field using ij unit vector notation. Enter precise fractions and roots rather than entering their approximate numerical values. E→net =

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