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For the circuit above, at zero input condition( (v1 = v2 = 0), VD1_0 = VD2_0 = 6 V, the amplification matrix is defined as[vod voc] = [Add Acd Adc Acc][vid vic]where Vid = v1-v2, Vic = (v1+v2)/2, Vod = vD1-vD2, Voc = (vD1+vD2)/2. Given Add = -89, Acd = 0.2, Adc = 0.1, Acc = −0.20, and v1 = −1.01, v2 = −0.98 determine the potential difference between VD1 and ground. (VD1 = VD1_0+vD1 and VD2 = VD2_0+vD2)

For the circuit above, at zero input condition( (v1 = v2 = 0), VD1_0 = VD2_0 = 6 V, the amplification matrix is defined as[vod voc] = [Add Acd Adc Acc][vid vic]where Vid = v1-v2, Vic = (v1+v2)/2, Vod = vD1-vD2, Voc = (vD1+vD2)/2. Given Add = -89, Acd = 0.2, Adc = 0.1, Acc = −0.20, and v1 = −1.01, v2 = −0.98 determine the potential difference between VD1 and ground. (VD1 = VD1_0+vD1 and VD2 = VD2_0+vD2)

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