Question

Notify Me Bookmark

(a) Three point charges are located on the circumference of a circle of radius r, at the angles shown in the figure. What is the electric field at the center of the circle due to these point charges? (Express your answer in vector form. Use the following as necessary: ke, q, and r. ) E→ = (b) What If? What is the minimum electric field magnitude that could be obtained at the center of the circle by moving one or more of the charges along the circle, with a minimum separation of 6.50∘ between each of the charges? Express your result as the ratio of this new electric field magnitude to the magnitude of the electric field found in part (a). Eminimum Epart (a) =

(a) Three point charges are located on the circumference of a circle of radius r, at the angles shown in the figure. What is the electric field at the center of the circle due to these point charges? (Express your answer in vector form. Use the following as necessary: ke, q, and r. ) E→ = (b) What If? What is the minimum electric field magnitude that could be obtained at the center of the circle by moving one or more of the charges along the circle, with a minimum separation of 6.50∘ between each of the charges? Express your result as the ratio of this new electric field magnitude to the magnitude of the electric field found in part (a). Eminimum Epart (a) =

Image text
(a) Three point charges are located on the circumference of a circle of radius r , at the angles shown in the figure. What is the electric field at the center of the circle due to these point charges? (Express your answer in vector form. Use the following as necessary: k e , q , and r . )
E → = ◻
(b) What If? What is the minimum electric field magnitude that could be obtained at the center of the circle by moving one or more of the charges along the circle, with a minimum separation of 6.50 ∘ between each of the charges? Express your result as the ratio of this new electric field magnitude to the magnitude of the electric field found in part (a). E minimum E part (a) = ◻

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

(a) Three point charges are located on the circumference of a circle of radius r, at the angles shown in the figure. What is the electric field at the center of the circle due to these point charges? (Express your answer in vector form. Use the following as necessary: ke, q, and r.) E→ = (b) What If? What is the minimum electric field magnitude that could be obtained at the center of the circle by moving one or more of the charges along the circle, with a minimum separation of 6.10∘ between each of the charges? Express your result as the ratio of this new electric field magnitude to the magnitude of the electric field found in part (a). Eminimum Epart (a) =
Solution
0 0

An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a distance d. (a) What is the magnitude of the electric field? (Use any variable or symbol stated above along with the following as necessary: e for the charge of the electron.) E = (b) What is the direction of the electric field? in the direction of the electron's motion opposite to the direction of the electron's motion perpendicular to the direction of the electron's motion (c) What If? Fluoride ions (which have the same charge as an electron) are initially moving with the same speed as the electrons from part (a) through a different uniform electric field. The ions come to a stop in the same distance d. Let the mass of an ion be M and the mass of an electron be m. Find the ratio of the magnitude of electric field the ions travel through to the magnitude of the electric field found in part (a). (Use the following as necessary: d, k, m, M, and e for the charge of the electron.) Enew Epart (a) =
Solution
3 0

In the figure below, each charged particle is located at one of the four vertices of a square with side length = a. In the figure, A = 3, B = 4, and C = 3, and q > 0. (i) (a) What is the expression for the magnitude of the electric field in the upper right corner of the square (at the location of q )? (Use the following as necessary: q, a, and ke⋅) E = Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric field at this location. (counterclockwise from the +x-axis) (b) Determine the expression for the total electric force exerted on the charge q. (Enter the magnitude. Use the following as necessary: q, a, and ke. ) F = Give the direction angle (in degrees counterclockwise from the +x-axis) of the electric force on q. ∘ (counterclockwise from the +x-axis) (c) What If? How would the answers to parts (a) and (b) change if each of the four charges were negative with the same magnitude? Select all that apply. The force would be the same magnitude but opposite direction as the force in part (b). The electric field would be the same magnitude and direction as the field in part (a). The force would be the same magnitude and direction as the force in part (b). The electric field would be the same magnitude but opposite direction as the field in part (a).
Solution
0 0